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315006231398897 is a prime number
BaseRepresentation
bin100011110011111110001101…
…0100001100100100111110001
31112022100022010212202211101102
41013213330122201210213301
5312242030230214231042
63033543510454214145
7123231310032665333
oct10747743241444761
91468308125684342
10315006231398897
119140943547a245
122b3b6399654355
131069cc6361c27c
1457b0550b53453
15266407d0b8b32
hex11e7f1a8649f1

315006231398897 has 2 divisors, whose sum is σ = 315006231398898. Its totient is φ = 315006231398896.

The previous prime is 315006231398893. The next prime is 315006231398899. The reversal of 315006231398897 is 798893132600513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 182776447626256 + 132229783772641 = 13519484^2 + 11499121^2 .

It is a cyclic number.

It is not a de Polignac number, because 315006231398897 - 22 = 315006231398893 is a prime.

Together with 315006231398899, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (315006231398893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157503115699448 + 157503115699449.

It is an arithmetic number, because the mean of its divisors is an integer number (157503115699449).

Almost surely, 2315006231398897 is an apocalyptic number.

It is an amenable number.

315006231398897 is a deficient number, since it is larger than the sum of its proper divisors (1).

315006231398897 is an equidigital number, since it uses as much as digits as its factorization.

315006231398897 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58786560, while the sum is 65.

The spelling of 315006231398897 in words is "three hundred fifteen trillion, six billion, two hundred thirty-one million, three hundred ninety-eight thousand, eight hundred ninety-seven".