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3150071011423 = 7752959770241
BaseRepresentation
bin101101110101101110110…
…111010001100001011111
3102011010212212100112200101
4231311232313101201133
5403102321134331143
610411042254041531
7443404460543530
oct55655667214137
912133785315611
103150071011423
111004a34a66856
1242a6084a92a7
1319b086a1334b
14ac66dc90687
1556e1969db4d
hex2dd6edd185f

3150071011423 has 8 divisors (see below), whose sum is σ = 3600559378080. Its totient is φ = 2699702200320.

The previous prime is 3150071011391. The next prime is 3150071011429. The reversal of 3150071011423 is 3241101700513.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 3150071011423 - 25 = 3150071011391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3150071011391 and 3150071011400.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3150071011429) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29832418 + ... + 29937823.

It is an arithmetic number, because the mean of its divisors is an integer number (450069922260).

Almost surely, 23150071011423 is an apocalyptic number.

3150071011423 is a deficient number, since it is larger than the sum of its proper divisors (450488366657).

3150071011423 is an equidigital number, since it uses as much as digits as its factorization.

3150071011423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 59777777.

The product of its (nonzero) digits is 2520, while the sum is 28.

Adding to 3150071011423 its reverse (3241101700513), we get a palindrome (6391172711936).

The spelling of 3150071011423 in words is "three trillion, one hundred fifty billion, seventy-one million, eleven thousand, four hundred twenty-three".

Divisors: 1 7 7529 52703 59770241 418391687 450010144489 3150071011423