Base | Representation |
---|---|
bin | 100011110100000000100111… |
… | …0111011000001001100010110 |
3 | 1112022100210111110122221222211 |
4 | 1013220001032323001030112 |
5 | 312242121324243431204 |
6 | 3033550124124144034 |
7 | 123231552200502403 |
oct | 10750011673011426 |
9 | 1468323443587884 |
10 | 315011405452054 |
11 | 91410650057a33 |
12 | 2b3b73a239801a |
13 | 106a05a954bc9c |
14 | 57b08c1da12aa |
15 | 2664282451804 |
hex | 11e804eec1316 |
315011405452054 has 4 divisors (see below), whose sum is σ = 472517108178084. Its totient is φ = 157505702726026.
The previous prime is 315011405451929. The next prime is 315011405452063. The reversal of 315011405452054 is 450254504110513.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 315011405451998 and 315011405452016.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78752851363012 + ... + 78752851363015.
It is an arithmetic number, because the mean of its divisors is an integer number (118129277044521).
Almost surely, 2315011405452054 is an apocalyptic number.
315011405452054 is a deficient number, since it is larger than the sum of its proper divisors (157505702726030).
315011405452054 is a wasteful number, since it uses less digits than its factorization.
315011405452054 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 157505702726029.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 315011405452054 its reverse (450254504110513), we get a palindrome (765265909562567).
The spelling of 315011405452054 in words is "three hundred fifteen trillion, eleven billion, four hundred five million, four hundred fifty-two thousand, fifty-four".
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