Base | Representation |
---|---|
bin | 1011101111000011… |
… | …0110000100100101 |
3 | 22010112112212212220 |
4 | 2323300312010211 |
5 | 22422414100111 |
6 | 1240330302553 |
7 | 141030531441 |
oct | 27360660445 |
9 | 8115485786 |
10 | 3150143781 |
11 | 13771a0714 |
12 | 73ab87a59 |
13 | 3b2833a05 |
14 | 21c52b821 |
15 | 136850e06 |
hex | bbc36125 |
3150143781 has 8 divisors (see below), whose sum is σ = 4205373984. Its totient is φ = 2097504720.
The previous prime is 3150143749. The next prime is 3150143783. The reversal of 3150143781 is 1873410513.
3150143781 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3150143781 - 25 = 3150143749 is a prime.
It is a super-2 number, since 2×31501437812 = 19846811681945951922, which contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3150143783) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 644946 + ... + 649811.
It is an arithmetic number, because the mean of its divisors is an integer number (525671748).
Almost surely, 23150143781 is an apocalyptic number.
It is an amenable number.
3150143781 is a deficient number, since it is larger than the sum of its proper divisors (1055230203).
3150143781 is a wasteful number, since it uses less digits than its factorization.
3150143781 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1295571.
The product of its (nonzero) digits is 10080, while the sum is 33.
The square root of 3150143781 is about 56126.1416899469. The cubic root of 3150143781 is about 1465.9195120486.
The spelling of 3150143781 in words is "three billion, one hundred fifty million, one hundred forty-three thousand, seven hundred eighty-one".
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