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315023240423713 is a prime number
BaseRepresentation
bin100011110100000110001000…
…0010101110110100100100001
31112022101221001021020211000111
41013220030100111312210201
5312242320044022024323
63033555402340451321
7123232451366215063
oct10750142025664441
91468357037224014
10315023240423713
1191415673642348
122b3b97459a9b41
13106a17444523b3
1457b12c5b01733
152664726474c0d
hex11e8310576921

315023240423713 has 2 divisors, whose sum is σ = 315023240423714. Its totient is φ = 315023240423712.

The previous prime is 315023240423707. The next prime is 315023240423719. The reversal of 315023240423713 is 317324042320513.

It is a balanced prime because it is at equal distance from previous prime (315023240423707) and next prime (315023240423719).

It can be written as a sum of positive squares in only one way, i.e., 234155090724129 + 80868149699584 = 15302127^2 + 8992672^2 .

It is an emirp because it is prime and its reverse (317324042320513) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 315023240423713 - 245 = 279838868334881 is a prime.

It is not a weakly prime, because it can be changed into another prime (315023240423719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157511620211856 + 157511620211857.

It is an arithmetic number, because the mean of its divisors is an integer number (157511620211857).

Almost surely, 2315023240423713 is an apocalyptic number.

It is an amenable number.

315023240423713 is a deficient number, since it is larger than the sum of its proper divisors (1).

315023240423713 is an equidigital number, since it uses as much as digits as its factorization.

315023240423713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 362880, while the sum is 40.

The spelling of 315023240423713 in words is "three hundred fifteen trillion, twenty-three billion, two hundred forty million, four hundred twenty-three thousand, seven hundred thirteen".