Base | Representation |
---|---|
bin | 1001001010110010100… |
… | …00100111110100001110 |
3 | 1010010010222210100210021 |
4 | 10211121100213310032 |
5 | 20130140204022342 |
6 | 400420045132354 |
7 | 31521512012065 |
oct | 4453120476416 |
9 | 1103128710707 |
10 | 315030142222 |
11 | 111670336644 |
12 | 5107ab5a0ba |
13 | 2392699c5a3 |
14 | 113673711dc |
15 | 82dbe79567 |
hex | 4959427d0e |
315030142222 has 4 divisors (see below), whose sum is σ = 472545213336. Its totient is φ = 157515071110.
The previous prime is 315030142199. The next prime is 315030142277. The reversal of 315030142222 is 222241030513.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 222241030513 = 11491 ⋅19340443.
It is a super-3 number, since 3×3150301422223 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 78757535554 + ... + 78757535557.
It is an arithmetic number, because the mean of its divisors is an integer number (118136303334).
Almost surely, 2315030142222 is an apocalyptic number.
315030142222 is a deficient number, since it is larger than the sum of its proper divisors (157515071114).
315030142222 is a wasteful number, since it uses less digits than its factorization.
315030142222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 157515071113.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 315030142222 its reverse (222241030513), we get a palindrome (537271172735).
The spelling of 315030142222 in words is "three hundred fifteen billion, thirty million, one hundred forty-two thousand, two hundred twenty-two".
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