Base | Representation |
---|---|
bin | 1001001010110010110… |
… | …01101111010010000111 |
3 | 1010010011011021210002101 |
4 | 10211121121233102013 |
5 | 20130141312011403 |
6 | 400420212252531 |
7 | 31521541224502 |
oct | 4453131572207 |
9 | 1103134253071 |
10 | 315032532103 |
11 | 111671719153 |
12 | 5107b911147 |
13 | 23927328313 |
14 | 113677d4139 |
15 | 82dc29c71d |
hex | 495966f487 |
315032532103 has 4 divisors (see below), whose sum is σ = 315041337688. Its totient is φ = 315023726520.
The previous prime is 315032532071. The next prime is 315032532131. The reversal of 315032532103 is 301235230513.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301235230513 = 7 ⋅43033604359.
It is a cyclic number.
It is not a de Polignac number, because 315032532103 - 25 = 315032532071 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315032532203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4348908 + ... + 4420753.
It is an arithmetic number, because the mean of its divisors is an integer number (78760334422).
Almost surely, 2315032532103 is an apocalyptic number.
315032532103 is a deficient number, since it is larger than the sum of its proper divisors (8805585).
315032532103 is an equidigital number, since it uses as much as digits as its factorization.
315032532103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8805584.
The product of its (nonzero) digits is 8100, while the sum is 28.
Adding to 315032532103 its reverse (301235230513), we get a palindrome (616267762616).
The spelling of 315032532103 in words is "three hundred fifteen billion, thirty-two million, five hundred thirty-two thousand, one hundred three".
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