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315034354213 = 3110162398523
BaseRepresentation
bin1001001010110011000…
…00101100001000100101
31010010011021201100112221
410211121200230020211
520130142243313323
6400420315312341
731521562553665
oct4453140541045
91103137640487
10315034354213
11111672753127
125108044b6b1
13239278157a7
1411367b4a1a5
1582dc50c55d
hex495982c225

315034354213 has 4 divisors (see below), whose sum is σ = 325196752768. Its totient is φ = 304871955660.

The previous prime is 315034354127. The next prime is 315034354223. The reversal of 315034354213 is 312453430513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 315034354213 - 233 = 306444419621 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315034354223) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5081199231 + ... + 5081199292.

It is an arithmetic number, because the mean of its divisors is an integer number (81299188192).

Almost surely, 2315034354213 is an apocalyptic number.

It is an amenable number.

315034354213 is a deficient number, since it is larger than the sum of its proper divisors (10162398555).

315034354213 is a wasteful number, since it uses less digits than its factorization.

315034354213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10162398554.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 315034354213 its reverse (312453430513), we get a palindrome (627487784726).

The spelling of 315034354213 in words is "three hundred fifteen billion, thirty-four million, three hundred fifty-four thousand, two hundred thirteen".

Divisors: 1 31 10162398523 315034354213