Base | Representation |
---|---|
bin | 1001001010110011001… |
… | …00110000110101011100 |
3 | 1010010011100201121100020 |
4 | 10211121210300311130 |
5 | 20130143032001134 |
6 | 400420354232140 |
7 | 31521604622130 |
oct | 4453144606534 |
9 | 1103140647306 |
10 | 315035422044 |
11 | 111673312432 |
12 | 51080885650 |
13 | 23927aca845 |
14 | 11367d473c0 |
15 | 82dc66db49 |
hex | 4959930d5c |
315035422044 has 24 divisors (see below), whose sum is σ = 840094459008. Its totient is φ = 90010120560.
The previous prime is 315035422001. The next prime is 315035422069. The reversal of 315035422044 is 440224530513.
It is a super-2 number, since 2×3150354220442 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 315035421996 and 315035422014.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1875210762 + ... + 1875210929.
It is an arithmetic number, because the mean of its divisors is an integer number (35003935792).
Almost surely, 2315035422044 is an apocalyptic number.
It is an amenable number.
315035422044 is an abundant number, since it is smaller than the sum of its proper divisors (525059036964).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
315035422044 is a wasteful number, since it uses less digits than its factorization.
315035422044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3750421705 (or 3750421703 counting only the distinct ones).
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 315035422044 its reverse (440224530513), we get a palindrome (755259952557).
The spelling of 315035422044 in words is "three hundred fifteen billion, thirty-five million, four hundred twenty-two thousand, forty-four".
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