Base | Representation |
---|---|
bin | 101101110101111111110… |
… | …011011010011100001101 |
3 | 102011011121200010102122100 |
4 | 231311333303122130031 |
5 | 403103411413241140 |
6 | 10411130405305313 |
7 | 443414511321006 |
oct | 55657763323415 |
9 | 12134550112570 |
10 | 3150355212045 |
11 | 10050704299a8 |
12 | 42a687705239 |
13 | 19b10086b9b2 |
14 | ac6999101ad |
15 | 56e345db530 |
hex | 2dd7fcda70d |
3150355212045 has 48 divisors (see below), whose sum is σ = 5748341002560. Its totient is φ = 1591668569088.
The previous prime is 3150355212031. The next prime is 3150355212047. The reversal of 3150355212045 is 5402125530513.
3150355212045 is a `hidden beast` number, since 3 + 1 + 50 + 3 + 552 + 12 + 0 + 45 = 666.
It is not a de Polignac number, because 3150355212045 - 25 = 3150355212013 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3150355212047) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 16623594 + ... + 16812036.
It is an arithmetic number, because the mean of its divisors is an integer number (119757104220).
Almost surely, 23150355212045 is an apocalyptic number.
It is an amenable number.
3150355212045 is a deficient number, since it is larger than the sum of its proper divisors (2597985790515).
3150355212045 is a wasteful number, since it uses less digits than its factorization.
3150355212045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 208026 (or 208023 counting only the distinct ones).
The product of its (nonzero) digits is 90000, while the sum is 36.
The spelling of 3150355212045 in words is "three trillion, one hundred fifty billion, three hundred fifty-five million, two hundred twelve thousand, forty-five".
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