Base | Representation |
---|---|
bin | 101101110110000100111… |
… | …010110000011000011101 |
3 | 102011011211122121002011001 |
4 | 231312010322300120131 |
5 | 403104100400214010 |
6 | 10411143112430301 |
7 | 443416602565513 |
oct | 55660472603035 |
9 | 12134748532131 |
10 | 3150441023005 |
11 | 1005104909a51 |
12 | 42a6b03a8391 |
13 | 19b115585003 |
14 | ac6a708a4b3 |
15 | 56e3bddbc3a |
hex | 2dd84eb061d |
3150441023005 has 16 divisors (see below), whose sum is σ = 3928120945920. Its totient is φ = 2422724057152.
The previous prime is 3150441023003. The next prime is 3150441023017. The reversal of 3150441023005 is 5003201440513.
3150441023005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 3150441023005 - 21 = 3150441023003 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3150441023003) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47824309 + ... + 47890138.
It is an arithmetic number, because the mean of its divisors is an integer number (245507559120).
Almost surely, 23150441023005 is an apocalyptic number.
It is an amenable number.
3150441023005 is a deficient number, since it is larger than the sum of its proper divisors (777679922915).
3150441023005 is a wasteful number, since it uses less digits than its factorization.
3150441023005 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95714708.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 3150441023005 its reverse (5003201440513), we get a palindrome (8153642463518).
The spelling of 3150441023005 in words is "three trillion, one hundred fifty billion, four hundred forty-one million, twenty-three thousand, five".
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