315050400123311 has 4 divisors (see below), whose sum is σ = 316649640733272. Its totient is φ = 313451159513352.

The previous prime is 315050400123269. The next prime is 315050400123317. The reversal of 315050400123311 is 113321004050513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-315050400123311 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315050400123317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 799620304685 + ... + 799620305078.

It is an arithmetic number, because the mean of its divisors is an integer number (79162410183318).

Almost surely, 2^{315050400123311} is an apocalyptic number.

315050400123311 is a deficient number, since it is larger than the sum of its proper divisors (1599240609961).

315050400123311 is a wasteful number, since it uses less digits than its factorization.

315050400123311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1599240609960.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 315050400123311 its reverse (113321004050513), we get a palindrome (428371404173824).

The spelling of 315050400123311 in words is "three hundred fifteen trillion, fifty billion, four hundred million, one hundred twenty-three thousand, three hundred eleven".