Base | Representation |
---|---|
bin | 1001001010111011010… |
… | …00001010111001101111 |
3 | 1010010100002200110122022 |
4 | 10211131220022321233 |
5 | 20130312434032421 |
6 | 400431223540355 |
7 | 31523361624650 |
oct | 4453550127157 |
9 | 1103302613568 |
10 | 315103424111 |
11 | 1116a8739393 |
12 | 5109b5ba6bb |
13 | 23938c19b58 |
14 | 11372da9527 |
15 | 82e36027ab |
hex | 495da0ae6f |
315103424111 has 4 divisors (see below), whose sum is σ = 360118198992. Its totient is φ = 270088649232.
The previous prime is 315103424089. The next prime is 315103424137. The reversal of 315103424111 is 111424301513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 315103424111 - 230 = 314029682287 is a prime.
It is a super-2 number, since 2×3151034241112 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315103426111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22507387430 + ... + 22507387443.
It is an arithmetic number, because the mean of its divisors is an integer number (90029549748).
Almost surely, 2315103424111 is an apocalyptic number.
315103424111 is a deficient number, since it is larger than the sum of its proper divisors (45014774881).
315103424111 is an equidigital number, since it uses as much as digits as its factorization.
315103424111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 45014774880.
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 315103424111 its reverse (111424301513), we get a palindrome (426527725624).
The spelling of 315103424111 in words is "three hundred fifteen billion, one hundred three million, four hundred twenty-four thousand, one hundred eleven".
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