Base | Representation |
---|---|
bin | 1001001010111011011… |
… | …11111000010011101111 |
3 | 1010010100020111010220212 |
4 | 10211131233320103233 |
5 | 20130313443220403 |
6 | 400431335133035 |
7 | 31523415043031 |
oct | 4453557702357 |
9 | 1103306433825 |
10 | 315105445103 |
11 | 1116a9899829 |
12 | 510a021417b |
13 | 239394769c7 |
14 | 11373373c51 |
15 | 82e38a14d8 |
hex | 495dbf84ef |
315105445103 has 2 divisors, whose sum is σ = 315105445104. Its totient is φ = 315105445102.
The previous prime is 315105445093. The next prime is 315105445111. The reversal of 315105445103 is 301544501513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 315105445103 - 210 = 315105444079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 315105445103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315105445003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157552722551 + 157552722552.
It is an arithmetic number, because the mean of its divisors is an integer number (157552722552).
Almost surely, 2315105445103 is an apocalyptic number.
315105445103 is a deficient number, since it is larger than the sum of its proper divisors (1).
315105445103 is an equidigital number, since it uses as much as digits as its factorization.
315105445103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 32.
Adding to 315105445103 its reverse (301544501513), we get a palindrome (616649946616).
The spelling of 315105445103 in words is "three hundred fifteen billion, one hundred five million, four hundred forty-five thousand, one hundred three".
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