Base | Representation |
---|---|
bin | 1001001010111100000… |
… | …01001111000001111111 |
3 | 1010010100120001021200121 |
4 | 10211132001033001333 |
5 | 20130321124311443 |
6 | 400432020435411 |
7 | 31523501521654 |
oct | 4453601170177 |
9 | 1103316037617 |
10 | 315109994623 |
11 | 111701416966 |
12 | 510a1848b67 |
13 | 2393a3aa728 |
14 | 11373bd9c2b |
15 | 82e3e9e4ed |
hex | 495e04f07f |
315109994623 has 2 divisors, whose sum is σ = 315109994624. Its totient is φ = 315109994622.
The previous prime is 315109994579. The next prime is 315109994651. The reversal of 315109994623 is 326499901513.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 315109994623 - 233 = 306520060031 is a prime.
It is a super-2 number, since 2×3151099946232 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315109974623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157554997311 + 157554997312.
It is an arithmetic number, because the mean of its divisors is an integer number (157554997312).
Almost surely, 2315109994623 is an apocalyptic number.
315109994623 is a deficient number, since it is larger than the sum of its proper divisors (1).
315109994623 is an equidigital number, since it uses as much as digits as its factorization.
315109994623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1574640, while the sum is 52.
The spelling of 315109994623 in words is "three hundred fifteen billion, one hundred nine million, nine hundred ninety-four thousand, six hundred twenty-three".
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