Base | Representation |
---|---|
bin | 1001001010111100000… |
… | …10111100010011001111 |
3 | 1010010100120220000122012 |
4 | 10211132002330103033 |
5 | 20130321233122231 |
6 | 400432034211435 |
7 | 31523505364556 |
oct | 4453602742317 |
9 | 1103316800565 |
10 | 315110442191 |
11 | 1117016a2156 |
12 | 510a1a23b7b |
13 | 2393a50636c |
14 | 11373cb4d9d |
15 | 82e403be2b |
hex | 495e0bc4cf |
315110442191 has 2 divisors, whose sum is σ = 315110442192. Its totient is φ = 315110442190.
The previous prime is 315110442167. The next prime is 315110442197. The reversal of 315110442191 is 191244011513.
It is a strong prime.
It is an emirp because it is prime and its reverse (191244011513) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 315110442191 - 210 = 315110441167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315110442197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157555221095 + 157555221096.
It is an arithmetic number, because the mean of its divisors is an integer number (157555221096).
Almost surely, 2315110442191 is an apocalyptic number.
315110442191 is a deficient number, since it is larger than the sum of its proper divisors (1).
315110442191 is an equidigital number, since it uses as much as digits as its factorization.
315110442191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 32.
The spelling of 315110442191 in words is "three hundred fifteen billion, one hundred ten million, four hundred forty-two thousand, one hundred ninety-one".
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