315121001153 has 4 divisors (see below), whose sum is σ = 360138287040. Its totient is φ = 270103715268.

The previous prime is 315121001147. The next prime is 315121001179. The reversal of 315121001153 is 351100121513.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 351100121513 = 93491 ⋅3755443.

It is a cyclic number.

It is not a de Polignac number, because 315121001153 - 2⁴ = 315121001137 is a prime.

It is not an unprimeable number, because it can be changed into a prime (315121001113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22508642933 + ... + 22508642946.

It is an arithmetic number, because the mean of its divisors is an integer number (90034571760).

Almost surely, 2^315121001153 is an apocalyptic number.

It is an amenable number.

315121001153 is a deficient number, since it is larger than the sum of its proper divisors (45017285887).

315121001153 is an equidigital number, since it uses as much as digits as its factorization.

315121001153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45017285886.

The product of its (nonzero) digits is 450, while the sum is 23.

Adding to 315121001153 its reverse (351100121513), we get a palindrome (666221122666).

The spelling of 315121001153 in words is "three hundred fifteen billion, one hundred twenty-one million, one thousand, one hundred fifty-three".