Base | Representation |
---|---|
bin | 1110010101001001101110… |
… | …10101111000110101010101 |
3 | 11010120121211100221110121021 |
4 | 13022210313111320311111 |
5 | 13112302314001113240 |
6 | 151004530411121141 |
7 | 6431514040261060 |
oct | 712446725706525 |
9 | 133517740843537 |
10 | 31513103535445 |
11 | a04a6a5445584 |
12 | 364b54a7431b1 |
13 | 147789950830c |
14 | 7ad3570138d7 |
15 | 399adc72754a |
hex | 1ca937578d55 |
31513103535445 has 16 divisors (see below), whose sum is σ = 43703565742080. Its totient is φ = 21366187691904.
The previous prime is 31513103535421. The next prime is 31513103535449. The reversal of 31513103535445 is 54453530131513.
It is a cyclic number.
It is not a de Polignac number, because 31513103535445 - 27 = 31513103535317 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31513103535449) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5058279957 + ... + 5058286186.
It is an arithmetic number, because the mean of its divisors is an integer number (2731472858880).
Almost surely, 231513103535445 is an apocalyptic number.
31513103535445 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
It is an amenable number.
31513103535445 is a deficient number, since it is larger than the sum of its proper divisors (12190462206635).
31513103535445 is a wasteful number, since it uses less digits than its factorization.
31513103535445 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10116566244.
The product of its (nonzero) digits is 810000, while the sum is 43.
Adding to 31513103535445 its reverse (54453530131513), we get a palindrome (85966633666958).
The spelling of 31513103535445 in words is "thirty-one trillion, five hundred thirteen billion, one hundred three million, five hundred thirty-five thousand, four hundred forty-five".
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