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315135010500 = 223532931233693
BaseRepresentation
bin1001001010111111000…
…00101010011011000100
31010010102022010020000120
410211133200222123010
520130344030314000
6400434312541540
731524224251362
oct4453740523304
91103368106016
10315135010500
11111714552742
12510aa0b18b0
1323942628c1b
141137726c632
1582e62916a0
hex495f82a6c4

315135010500 has 192 divisors, whose sum is σ = 979944376320. Its totient is φ = 78520512000.

The previous prime is 315135010483. The next prime is 315135010513. The reversal of 315135010500 is 5010531513.

It is a super-2 number, since 2×3151350105002 (a number of 24 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1231654 + ... + 1465346.

It is an arithmetic number, because the mean of its divisors is an integer number (5103876960).

Almost surely, 2315135010500 is an apocalyptic number.

315135010500 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 315135010500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (489972188160).

315135010500 is an abundant number, since it is smaller than the sum of its proper divisors (664809365820).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

315135010500 is a wasteful number, since it uses less digits than its factorization.

315135010500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233775 (or 233763 counting only the distinct ones).

The product of its (nonzero) digits is 1125, while the sum is 24.

The spelling of 315135010500 in words is "three hundred fifteen billion, one hundred thirty-five million, ten thousand, five hundred".