Base | Representation |
---|---|
bin | 101101110110111110001… |
… | …001111110110001111011 |
3 | 102011021022120112222201221 |
4 | 231312332021332301323 |
5 | 403113032214043301 |
6 | 10411422255052511 |
7 | 443452443130114 |
oct | 55667611766173 |
9 | 12137276488657 |
10 | 3151401315451 |
11 | 1005557981974 |
12 | 42a919b11137 |
13 | 19b2394cb7ac |
14 | ac75881d20b |
15 | 56e96377da1 |
hex | 2ddbe27ec7b |
3151401315451 has 8 divisors (see below), whose sum is σ = 3339528066000. Its totient is φ = 2965500917280.
The previous prime is 3151401315449. The next prime is 3151401315497. The reversal of 3151401315451 is 1545131041513.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 3151401315451 - 21 = 3151401315449 is a prime.
It is a super-2 number, since 2×31514013154512 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3151401615451) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 556585180 + ... + 556590841.
It is an arithmetic number, because the mean of its divisors is an integer number (417441008250).
Almost surely, 23151401315451 is an apocalyptic number.
3151401315451 is a deficient number, since it is larger than the sum of its proper divisors (188126750549).
3151401315451 is a wasteful number, since it uses less digits than its factorization.
3151401315451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1113176189.
The product of its (nonzero) digits is 18000, while the sum is 34.
Adding to 3151401315451 its reverse (1545131041513), we get a palindrome (4696532356964).
The spelling of 3151401315451 in words is "three trillion, one hundred fifty-one billion, four hundred one million, three hundred fifteen thousand, four hundred fifty-one".
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