Base | Representation |
---|---|
bin | 1001001010111111110… |
… | …01000010011101110001 |
3 | 1010010102202010212100202 |
4 | 10211133321002131301 |
5 | 20130402144303213 |
6 | 400435101524545 |
7 | 31524332464046 |
oct | 4453771023561 |
9 | 1103382125322 |
10 | 315141400433 |
11 | 111718117582 |
12 | 510b0273755 |
13 | 23943a55552 |
14 | 113780531cd |
15 | 82e6b04b58 |
hex | 495fe42771 |
315141400433 has 2 divisors, whose sum is σ = 315141400434. Its totient is φ = 315141400432.
The previous prime is 315141400417. The next prime is 315141400451. The reversal of 315141400433 is 334004141513.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 271803737104 + 43337663329 = 521348^2 + 208177^2 .
It is a cyclic number.
It is not a de Polignac number, because 315141400433 - 24 = 315141400417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 315141400396 and 315141400405.
It is not a weakly prime, because it can be changed into another prime (315141408433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157570700216 + 157570700217.
It is an arithmetic number, because the mean of its divisors is an integer number (157570700217).
Almost surely, 2315141400433 is an apocalyptic number.
It is an amenable number.
315141400433 is a deficient number, since it is larger than the sum of its proper divisors (1).
315141400433 is an equidigital number, since it uses as much as digits as its factorization.
315141400433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 315141400433 its reverse (334004141513), we get a palindrome (649145541946).
The spelling of 315141400433 in words is "three hundred fifteen billion, one hundred forty-one million, four hundred thousand, four hundred thirty-three".
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