Base | Representation |
---|---|
bin | 11101010110011001… |
… | …100101000101010111 |
3 | 10000100021202011222020 |
4 | 131112121211011113 |
5 | 1004020131122033 |
6 | 22251045104223 |
7 | 2163645163431 |
oct | 352631450527 |
9 | 100307664866 |
10 | 31514317143 |
11 | 12402012a01 |
12 | 61360b8073 |
13 | 2c8302ac4a |
14 | 174d5d7651 |
15 | c46a506b3 |
hex | 756665157 |
31514317143 has 4 divisors (see below), whose sum is σ = 42019089528. Its totient is φ = 21009544760.
The previous prime is 31514317129. The next prime is 31514317183. The reversal of 31514317143 is 34171341513.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 31514317143 - 225 = 31480762711 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (31514317183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5252386188 + ... + 5252386193.
It is an arithmetic number, because the mean of its divisors is an integer number (10504772382).
Almost surely, 231514317143 is an apocalyptic number.
31514317143 is a deficient number, since it is larger than the sum of its proper divisors (10504772385).
31514317143 is a wasteful number, since it uses less digits than its factorization.
31514317143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10504772384.
The product of its digits is 15120, while the sum is 33.
Adding to 31514317143 its reverse (34171341513), we get a palindrome (65685658656).
The spelling of 31514317143 in words is "thirty-one billion, five hundred fourteen million, three hundred seventeen thousand, one hundred forty-three".
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