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315200131231 = 656348026837
BaseRepresentation
bin1001001011000110110…
…01000101000010011111
31010010120211122200212111
410211203121011002133
520131012213144411
6400445000414451
731525644623626
oct4454331050237
91103524580774
10315200131231
11111748290927
1251107a77427
1323952c798bb
1411381b806bd
1582ebd56721
hex496364509f

315200131231 has 4 divisors (see below), whose sum is σ = 315248164632. Its totient is φ = 315152097832.

The previous prime is 315200131217. The next prime is 315200131249. The reversal of 315200131231 is 132131002513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 315200131231 - 221 = 315198034079 is a prime.

It is a super-2 number, since 2×3152001312312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (315200131201) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24006856 + ... + 24019981.

It is an arithmetic number, because the mean of its divisors is an integer number (78812041158).

Almost surely, 2315200131231 is an apocalyptic number.

315200131231 is a deficient number, since it is larger than the sum of its proper divisors (48033401).

315200131231 is an equidigital number, since it uses as much as digits as its factorization.

315200131231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48033400.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 315200131231 its reverse (132131002513), we get a palindrome (447331133744).

The spelling of 315200131231 in words is "three hundred fifteen billion, two hundred million, one hundred thirty-one thousand, two hundred thirty-one".

Divisors: 1 6563 48026837 315200131231