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3152130104143 = 4651677731693
BaseRepresentation
bin101101110111101001100…
…110000101101101001111
3102011100012100220021212201
4231313221212011231033
5403121030301313033
610412022451342331
7443506502543356
oct55675146055517
912140170807781
103152130104143
1110058a12a4679
1242aaa1bb19a7
1319b3244aa6c7
14ac7c752c99d
1556eda33547d
hex2dde9985b4f

3152130104143 has 4 divisors (see below), whose sum is σ = 3152807840488. Its totient is φ = 3151452367800.

The previous prime is 3152130104069. The next prime is 3152130104197. The reversal of 3152130104143 is 3414010312513.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 3152130104143 - 29 = 3152130103631 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3152130104443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 338861196 + ... + 338870497.

It is an arithmetic number, because the mean of its divisors is an integer number (788201960122).

Almost surely, 23152130104143 is an apocalyptic number.

3152130104143 is a deficient number, since it is larger than the sum of its proper divisors (677736345).

3152130104143 is an equidigital number, since it uses as much as digits as its factorization.

3152130104143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 677736344.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 3152130104143 its reverse (3414010312513), we get a palindrome (6566140416656).

The spelling of 3152130104143 in words is "three trillion, one hundred fifty-two billion, one hundred thirty million, one hundred four thousand, one hundred forty-three".

Divisors: 1 4651 677731693 3152130104143