Base | Representation |
---|---|
bin | 1001001011001000111… |
… | …00000111110110111111 |
3 | 1010010122001201121111211 |
4 | 10211210130013312333 |
5 | 20131031213101211 |
6 | 400450425225251 |
7 | 31526250203365 |
oct | 4454434076677 |
9 | 1103561647454 |
10 | 315217706431 |
11 | 1117571a5391 |
12 | 51111932227 |
13 | 239567c1424 |
14 | 11384237635 |
15 | 82ed678e21 |
hex | 4964707dbf |
315217706431 has 4 divisors (see below), whose sum is σ = 315278576200. Its totient is φ = 315156836664.
The previous prime is 315217706423. The next prime is 315217706437. The reversal of 315217706431 is 134607712513.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 134607712513 = 326351 ⋅412463.
It is a cyclic number.
It is not a de Polignac number, because 315217706431 - 23 = 315217706423 is a prime.
It is a super-2 number, since 2×3152177064312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (315217706437) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30427116 + ... + 30437473.
It is an arithmetic number, because the mean of its divisors is an integer number (78819644050).
Almost surely, 2315217706431 is an apocalyptic number.
315217706431 is a deficient number, since it is larger than the sum of its proper divisors (60869769).
315217706431 is an equidigital number, since it uses as much as digits as its factorization.
315217706431 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 60869768.
The product of its (nonzero) digits is 105840, while the sum is 40.
The spelling of 315217706431 in words is "three hundred fifteen billion, two hundred seventeen million, seven hundred six thousand, four hundred thirty-one".
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