31524404142053 has 2 divisors, whose sum is σ = 31524404142054. Its totient is φ = 31524404142052.

The previous prime is 31524404142013. The next prime is 31524404142067. The reversal of 31524404142053 is 35024140442513.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 31200469004644 + 323935137409 = 5585738^2 + 569153^2 .

It is a cyclic number.

It is not a de Polignac number, because 31524404142053 - 2¹⁰ = 31524404141029 is a prime.

It is a super-2 number, since 2×31524404142053² (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31524404141998 and 31524404142016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31524404142013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15762202071026 + 15762202071027.

It is an arithmetic number, because the mean of its divisors is an integer number (15762202071027).

Almost surely, 2^{31524404142053} is an apocalyptic number.

It is an amenable number.

31524404142053 is a deficient number, since it is larger than the sum of its proper divisors (1).

31524404142053 is an equidigital number, since it uses as much as digits as its factorization.

31524404142053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 38.

Adding to 31524404142053 its reverse (35024140442513), we get a palindrome (66548544584566).

The spelling of 31524404142053 in words is "thirty-one trillion, five hundred twenty-four billion, four hundred four million, one hundred forty-two thousand, fifty-three".