315250012241413 has 2 divisors, whose sum is σ = 315250012241414. Its totient is φ = 315250012241412.

The previous prime is 315250012241399. The next prime is 315250012241501. The reversal of 315250012241413 is 314142210052513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 295670157183844 + 19579855057569 = 17195062^2 + 4424913^2 .

It is an emirp because it is prime and its reverse (314142210052513) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-315250012241413 is a prime.

It is a super-2 number, since 2×315250012241413² (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (315250012241513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157625006120706 + 157625006120707.

It is an arithmetic number, because the mean of its divisors is an integer number (157625006120707).

Almost surely, 2^{315250012241413} is an apocalyptic number.

It is an amenable number.

315250012241413 is a deficient number, since it is larger than the sum of its proper divisors (1).

315250012241413 is an equidigital number, since it uses as much as digits as its factorization.

315250012241413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 315250012241413 its reverse (314142210052513), we get a palindrome (629392222293926).

The spelling of 315250012241413 in words is "three hundred fifteen trillion, two hundred fifty billion, twelve million, two hundred forty-one thousand, four hundred thirteen".