Base | Representation |
---|---|
bin | 11101010111001110… |
… | …000001011110110011 |
3 | 10000101020121122102011 |
4 | 131113032001132303 |
5 | 1004032141034242 |
6 | 22252255503351 |
7 | 2164203062461 |
oct | 352716013663 |
9 | 100336548364 |
10 | 31528064947 |
11 | 12409852925 |
12 | 613a827b57 |
13 | 2c85b32642 |
14 | 1751375831 |
15 | c47d68d17 |
hex | 7573817b3 |
31528064947 has 2 divisors, whose sum is σ = 31528064948. Its totient is φ = 31528064946.
The previous prime is 31528064927. The next prime is 31528064977. The reversal of 31528064947 is 74946082513.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 31528064947 - 219 = 31527540659 is a prime.
It is a super-2 number, since 2×315280649472 (a number of 22 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 31528064947.
It is not a weakly prime, because it can be changed into another prime (31528064917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15764032473 + 15764032474.
It is an arithmetic number, because the mean of its divisors is an integer number (15764032474).
It is a 1-persistent number, because it is pandigital, but 2⋅31528064947 = 63056129894 is not.
Almost surely, 231528064947 is an apocalyptic number.
31528064947 is a deficient number, since it is larger than the sum of its proper divisors (1).
31528064947 is an equidigital number, since it uses as much as digits as its factorization.
31528064947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1451520, while the sum is 49.
The spelling of 31528064947 in words is "thirty-one billion, five hundred twenty-eight million, sixty-four thousand, nine hundred forty-seven".
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