Base | Representation |
---|---|
bin | 11101010111101001… |
… | …101010010011011001 |
3 | 10000101202020201210222 |
4 | 131113221222103121 |
5 | 1004041014410131 |
6 | 22253115045425 |
7 | 2164321466264 |
oct | 352751522331 |
9 | 100352221728 |
10 | 31535310041 |
11 | 12412951204 |
12 | 6141140875 |
13 | 2c8749b291 |
14 | 17522ddcdb |
15 | c487ea87b |
hex | 757a6a4d9 |
31535310041 has 2 divisors, whose sum is σ = 31535310042. Its totient is φ = 31535310040.
The previous prime is 31535310019. The next prime is 31535310043. The reversal of 31535310041 is 14001353513.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 26643706441 + 4891603600 = 163229^2 + 69940^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-31535310041 is a prime.
Together with 31535310043, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (31535310043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15767655020 + 15767655021.
It is an arithmetic number, because the mean of its divisors is an integer number (15767655021).
Almost surely, 231535310041 is an apocalyptic number.
It is an amenable number.
31535310041 is a deficient number, since it is larger than the sum of its proper divisors (1).
31535310041 is an equidigital number, since it uses as much as digits as its factorization.
31535310041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2700, while the sum is 26.
Adding to 31535310041 its reverse (14001353513), we get a palindrome (45536663554).
The spelling of 31535310041 in words is "thirty-one billion, five hundred thirty-five million, three hundred ten thousand, forty-one".
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