Base | Representation |
---|---|
bin | 11101010111111011… |
… | …111011110110010001 |
3 | 10000102002021010002021 |
4 | 131113323323312101 |
5 | 1004043231203442 |
6 | 22253405451441 |
7 | 2164410300523 |
oct | 352773736621 |
9 | 100362233067 |
10 | 31540100497 |
11 | 12415623364 |
12 | 6142870b81 |
13 | 2c88487879 |
14 | 1752bc9a13 |
15 | c48e44e67 |
hex | 757efbd91 |
31540100497 has 2 divisors, whose sum is σ = 31540100498. Its totient is φ = 31540100496.
The previous prime is 31540100477. The next prime is 31540100531. The reversal of 31540100497 is 79400104513.
It is an a-pointer prime, because the next prime (31540100531) can be obtained adding 31540100497 to its sum of digits (34).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25436741121 + 6103359376 = 159489^2 + 78124^2 .
It is a cyclic number.
It is not a de Polignac number, because 31540100497 - 215 = 31540067729 is a prime.
It is not a weakly prime, because it can be changed into another prime (31540100467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15770050248 + 15770050249.
It is an arithmetic number, because the mean of its divisors is an integer number (15770050249).
Almost surely, 231540100497 is an apocalyptic number.
It is an amenable number.
31540100497 is a deficient number, since it is larger than the sum of its proper divisors (1).
31540100497 is an equidigital number, since it uses as much as digits as its factorization.
31540100497 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15120, while the sum is 34.
The spelling of 31540100497 in words is "thirty-one billion, five hundred forty million, one hundred thousand, four hundred ninety-seven".
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