Base | Representation |
---|---|
bin | 100011110110110110001001… |
… | …1000100110111010101110001 |
3 | 1112100202001201221120211022102 |
4 | 1013231230103010313111301 |
5 | 312320013221304032423 |
6 | 3034445155252550145 |
7 | 123301662556544660 |
oct | 10755542304672561 |
9 | 1470661657524272 |
10 | 315401243424113 |
11 | 91550a09468330 |
12 | 2b45aa5a322355 |
13 | 106cb29574c332 |
14 | 57c57046a4dd7 |
15 | 266e49bb33c28 |
hex | 11edb13137571 |
315401243424113 has 8 divisors (see below), whose sum is σ = 393227524269120. Its totient is φ = 245767202668080.
The previous prime is 315401243424083. The next prime is 315401243424251. The reversal of 315401243424113 is 311424342104513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 315401243424113 - 228 = 315400974988657 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315401243420113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2048060022158 + ... + 2048060022311.
It is an arithmetic number, because the mean of its divisors is an integer number (49153440533640).
Almost surely, 2315401243424113 is an apocalyptic number.
It is an amenable number.
315401243424113 is a deficient number, since it is larger than the sum of its proper divisors (77826280845007).
315401243424113 is a wasteful number, since it uses less digits than its factorization.
315401243424113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4096120044487.
The product of its (nonzero) digits is 138240, while the sum is 38.
Adding to 315401243424113 its reverse (311424342104513), we get a palindrome (626825585528626).
The spelling of 315401243424113 in words is "three hundred fifteen trillion, four hundred one billion, two hundred forty-three million, four hundred twenty-four thousand, one hundred thirteen".
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