Base | Representation |
---|---|
bin | 1110010101111100000101… |
… | …11110010001000010010011 |
3 | 11010200012121201222201110001 |
4 | 13022332002332101002103 |
5 | 13113223202401342230 |
6 | 151025201415550431 |
7 | 6433462061253406 |
oct | 712760276210223 |
9 | 133605551881401 |
10 | 31540142215315 |
11 | a0601100379a8 |
12 | 365483598b417 |
13 | 147a2b820c886 |
14 | 7b07a0043d3d |
15 | 39a67139d0ca |
hex | 1caf82f91093 |
31540142215315 has 8 divisors (see below), whose sum is σ = 38653450885440. Its totient is φ = 24695260287552.
The previous prime is 31540142215313. The next prime is 31540142215349. The reversal of 31540142215315 is 51351224104513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 31540142215315 - 21 = 31540142215313 is a prime.
It is not an unprimeable number, because it can be changed into a prime (31540142215313) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 67106685330 + ... + 67106685799.
It is an arithmetic number, because the mean of its divisors is an integer number (4831681360680).
Almost surely, 231540142215315 is an apocalyptic number.
31540142215315 is a deficient number, since it is larger than the sum of its proper divisors (7113308670125).
31540142215315 is a wasteful number, since it uses less digits than its factorization.
31540142215315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 134213371181.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 31540142215315 its reverse (51351224104513), we get a palindrome (82891366319828).
The spelling of 31540142215315 in words is "thirty-one trillion, five hundred forty billion, one hundred forty-two million, two hundred fifteen thousand, three hundred fifteen".
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