Base | Representation |
---|---|
bin | 1110010101111100010000… |
… | …11110000111110000100001 |
3 | 11010200012212011112211101121 |
4 | 13022332020132013300201 |
5 | 13113223400004431001 |
6 | 151025214512532241 |
7 | 6433464261253132 |
oct | 712761036076041 |
9 | 133605764484347 |
10 | 31540234452001 |
11 | a060158106770 |
12 | 3654860851081 |
13 | 147a3013658b2 |
14 | 7b07ac3b3c89 |
15 | 39a67951c6a1 |
hex | 1caf88787c21 |
31540234452001 has 16 divisors (see below), whose sum is σ = 37197328109760. Its totient is φ = 26429680486080.
The previous prime is 31540234451987. The next prime is 31540234452011. The reversal of 31540234452001 is 10025443204513.
It is a cyclic number.
It is not a de Polignac number, because 31540234452001 - 29 = 31540234451489 is a prime.
It is a super-3 number, since 3×315402344520013 (a number of 41 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (31540234452011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2039319466 + ... + 2039334931.
It is an arithmetic number, because the mean of its divisors is an integer number (2324833006860).
Almost surely, 231540234452001 is an apocalyptic number.
It is an amenable number.
31540234452001 is a deficient number, since it is larger than the sum of its proper divisors (5657093657759).
31540234452001 is a wasteful number, since it uses less digits than its factorization.
31540234452001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4078654464.
The product of its (nonzero) digits is 57600, while the sum is 34.
Adding to 31540234452001 its reverse (10025443204513), we get a palindrome (41565677656514).
The spelling of 31540234452001 in words is "thirty-one trillion, five hundred forty billion, two hundred thirty-four million, four hundred fifty-two thousand, one".
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