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31544424113297 is a prime number
BaseRepresentation
bin1110010110000100000100…
…01100011010010010010001
311010200121200011010200020012
413023002002030122102101
513113310440033111142
6151031150335524305
76434003143634114
oct713020214322221
9133617604120205
1031544424113297
11a061a08061267
12365562b989695
13147a81b361814
147b0a889b857b
1539a822258882
hex1cb08231a491

31544424113297 has 2 divisors, whose sum is σ = 31544424113298. Its totient is φ = 31544424113296.

The previous prime is 31544424113287. The next prime is 31544424113329. The reversal of 31544424113297 is 79231142444513.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 27415790248081 + 4128633865216 = 5236009^2 + 2031904^2 .

It is a cyclic number.

It is not a de Polignac number, because 31544424113297 - 26 = 31544424113233 is a prime.

It is a super-3 number, since 3×315444241132973 (a number of 41 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (31544424113287) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15772212056648 + 15772212056649.

It is an arithmetic number, because the mean of its divisors is an integer number (15772212056649).

Almost surely, 231544424113297 is an apocalyptic number.

It is an amenable number.

31544424113297 is a deficient number, since it is larger than the sum of its proper divisors (1).

31544424113297 is an equidigital number, since it uses as much as digits as its factorization.

31544424113297 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2903040, while the sum is 50.

The spelling of 31544424113297 in words is "thirty-one trillion, five hundred forty-four billion, four hundred twenty-four million, one hundred thirteen thousand, two hundred ninety-seven".