Base | Representation |
---|---|
bin | 1001001011101010101… |
… | …10110101101110110011 |
3 | 1010011100211210112220212 |
4 | 10211311112311232303 |
5 | 20132121343043011 |
6 | 400534524454335 |
7 | 31536264535400 |
oct | 4456526655663 |
9 | 1104324715825 |
10 | 315501534131 |
11 | 111892433333 |
12 | 511909aa3ab |
13 | 239a0549104 |
14 | 113adbdb2a7 |
15 | 831854108b |
hex | 49755b5bb3 |
315501534131 has 6 divisors (see below), whose sum is σ = 367011988740. Its totient is φ = 270429886356.
The previous prime is 315501534091. The next prime is 315501534143. The reversal of 315501534131 is 131435105513.
It is not a de Polignac number, because 315501534131 - 210 = 315501533107 is a prime.
It is a super-2 number, since 2×3155015341312 (a number of 24 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (315501534031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 3219403361 + ... + 3219403458.
It is an arithmetic number, because the mean of its divisors is an integer number (61168664790).
Almost surely, 2315501534131 is an apocalyptic number.
315501534131 is a deficient number, since it is larger than the sum of its proper divisors (51510454609).
315501534131 is an equidigital number, since it uses as much as digits as its factorization.
315501534131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6438806833 (or 6438806826 counting only the distinct ones).
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 315501534131 its reverse (131435105513), we get a palindrome (446936639644).
The spelling of 315501534131 in words is "three hundred fifteen billion, five hundred one million, five hundred thirty-four thousand, one hundred thirty-one".
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