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315516563512417 is a prime number
BaseRepresentation
bin100011110111101011110110…
…0101100000101110001100001
31112101011002101210200021212001
41013233113230230011301201
5312323410410224344132
63035014150330404001
7123313214401246651
oct10757275454056141
91471132353607761
10315516563512417
119159590666a533
122b479282890601
13107091131ba287
1457cb12426c361
15267249ad0dce7
hex11ef5ecb05c61

315516563512417 has 2 divisors, whose sum is σ = 315516563512418. Its totient is φ = 315516563512416.

The previous prime is 315516563512387. The next prime is 315516563512459. The reversal of 315516563512417 is 714215365615513.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 294037750805841 + 21478812706576 = 17147529^2 + 4634524^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-315516563512417 is a prime.

It is a super-2 number, since 2×3155165635124172 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (315516563512487) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157758281756208 + 157758281756209.

It is an arithmetic number, because the mean of its divisors is an integer number (157758281756209).

Almost surely, 2315516563512417 is an apocalyptic number.

It is an amenable number.

315516563512417 is a deficient number, since it is larger than the sum of its proper divisors (1).

315516563512417 is an equidigital number, since it uses as much as digits as its factorization.

315516563512417 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11340000, while the sum is 55.

The spelling of 315516563512417 in words is "three hundred fifteen trillion, five hundred sixteen billion, five hundred sixty-three million, five hundred twelve thousand, four hundred seventeen".