Base | Representation |
---|---|
bin | 100011110111111101000000… |
… | …1110101000100100101101101 |
3 | 1112101021121112202211201200101 |
4 | 1013233322001311010211231 |
5 | 312330011403401113123 |
6 | 3035043124205031101 |
7 | 123315661022231221 |
oct | 10757720165044555 |
9 | 1471247482751611 |
10 | 315553425410413 |
11 | 915aa502202043 |
12 | 2b48444b855491 |
13 | 1070c739093b38 |
14 | 57ccc1db64781 |
15 | 2673407072aad |
hex | 11efe81d4496d |
315553425410413 has 2 divisors, whose sum is σ = 315553425410414. Its totient is φ = 315553425410412.
The previous prime is 315553425410389. The next prime is 315553425410467. The reversal of 315553425410413 is 314014524355513.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 241984842563044 + 73568582847369 = 15555862^2 + 8577213^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-315553425410413 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (315553425410213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 157776712705206 + 157776712705207.
It is an arithmetic number, because the mean of its divisors is an integer number (157776712705207).
Almost surely, 2315553425410413 is an apocalyptic number.
It is an amenable number.
315553425410413 is a deficient number, since it is larger than the sum of its proper divisors (1).
315553425410413 is an equidigital number, since it uses as much as digits as its factorization.
315553425410413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160000, while the sum is 46.
Adding to 315553425410413 its reverse (314014524355513), we get a palindrome (629567949765926).
The spelling of 315553425410413 in words is "three hundred fifteen trillion, five hundred fifty-three billion, four hundred twenty-five million, four hundred ten thousand, four hundred thirteen".
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