Base | Representation |
---|---|
bin | 101101111010110101100… |
… | …001000010001100110101 |
3 | 102011200000210112122000011 |
4 | 231322311201002030311 |
5 | 403200032120044000 |
6 | 10413350144220221 |
7 | 443660334520144 |
oct | 55726541021465 |
9 | 12150023478004 |
10 | 3155551331125 |
11 | 1007297509096 |
12 | 42b69790a671 |
13 | 19b74b22627b |
14 | aca2da6375b |
15 | 5713a8822ba |
hex | 2deb5842335 |
3155551331125 has 16 divisors (see below), whose sum is σ = 3969136963584. Its totient is φ = 2504563563600.
The previous prime is 3155551331123. The next prime is 3155551331137. The reversal of 3155551331125 is 5211331555513.
3155551331125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3155551331125 - 21 = 3155551331123 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3155551331123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 99371569 + ... + 99403318.
It is an arithmetic number, because the mean of its divisors is an integer number (248071060224).
Almost surely, 23155551331125 is an apocalyptic number.
It is an amenable number.
3155551331125 is a deficient number, since it is larger than the sum of its proper divisors (813585632459).
3155551331125 is a wasteful number, since it uses less digits than its factorization.
3155551331125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 198775029 (or 198775019 counting only the distinct ones).
The product of its digits is 168750, while the sum is 40.
Adding to 3155551331125 its reverse (5211331555513), we get a palindrome (8366882886638).
The spelling of 3155551331125 in words is "three trillion, one hundred fifty-five billion, five hundred fifty-one million, three hundred thirty-one thousand, one hundred twenty-five".
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