Base | Representation |
---|---|
bin | 11101011001101101… |
… | …111111100010000001 |
3 | 10000111011112011111022 |
4 | 131121231333202001 |
5 | 1004123410000001 |
6 | 22300354355225 |
7 | 2165222400221 |
oct | 353155774201 |
9 | 100434464438 |
10 | 31570000001 |
11 | 124304952a1 |
12 | 615088bb15 |
13 | 2c91725b97 |
14 | 1756b70081 |
15 | c4b89e11b |
hex | 759b7f881 |
31570000001 has 4 divisors (see below), whose sum is σ = 31570407600. Its totient is φ = 31569592404.
The previous prime is 31569999997. The next prime is 31570000037. The reversal of 31570000001 is 10000007513.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 31570000001 - 22 = 31569999997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (31570000081) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47831 + ... + 255788.
It is an arithmetic number, because the mean of its divisors is an integer number (7892601900).
Almost surely, 231570000001 is an apocalyptic number.
It is an amenable number.
31570000001 is a deficient number, since it is larger than the sum of its proper divisors (407599).
31570000001 is a wasteful number, since it uses less digits than its factorization.
31570000001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 407598.
The product of its (nonzero) digits is 105, while the sum is 17.
Adding to 31570000001 its reverse (10000007513), we get a palindrome (41570007514).
The spelling of 31570000001 in words is "thirty-one billion, five hundred seventy million, one", and thus it is an aban number.
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