Base | Representation |
---|---|
bin | 101101111100011010111… |
… | …000111111101101101101 |
3 | 102011211102022212012200021 |
4 | 231330122320333231231 |
5 | 403212023020024323 |
6 | 10414231022002141 |
7 | 444050436101524 |
oct | 55743270775555 |
9 | 12154368765607 |
10 | 3157252111213 |
11 | 1007a8a564372 |
12 | 42ba91416351 |
13 | 19b95c6b6915 |
14 | acb518ad4bb |
15 | 571d9d3c05d |
hex | 2df1ae3fb6d |
3157252111213 has 8 divisors (see below), whose sum is σ = 3204422545280. Its totient is φ = 3110083067520.
The previous prime is 3157252111201. The next prime is 3157252111219. The reversal of 3157252111213 is 3121112527513.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3157252111213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (3157252111219) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4791148 + ... + 5410138.
It is an arithmetic number, because the mean of its divisors is an integer number (400552818160).
Almost surely, 23157252111213 is an apocalyptic number.
It is an amenable number.
3157252111213 is a deficient number, since it is larger than the sum of its proper divisors (47170434067).
3157252111213 is an equidigital number, since it uses as much as digits as its factorization.
3157252111213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 695187.
The product of its digits is 12600, while the sum is 34.
Adding to 3157252111213 its reverse (3121112527513), we get a palindrome (6278364638726).
The spelling of 3157252111213 in words is "three trillion, one hundred fifty-seven billion, two hundred fifty-two million, one hundred eleven thousand, two hundred thirteen".
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