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316025542213013 is a prime number
BaseRepresentation
bin100011111011011000110111…
…0001011101111110110010101
31112102221202011101220020211002
41013312301232023233312111
5312410230302301304023
63040044044014353045
7123365043353650103
oct10766615613576625
91472852141806732
10316025542213013
11917717528a0646
122b53ba4a7bb785
131074510856b629
145807a09b20c73
152680839d12b28
hex11f6c6e2efd95

316025542213013 has 2 divisors, whose sum is σ = 316025542213014. Its totient is φ = 316025542213012.

The previous prime is 316025542212971. The next prime is 316025542213039. The reversal of 316025542213013 is 310312245520613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 271315484325649 + 44710057887364 = 16471657^2 + 6686558^2 .

It is a cyclic number.

It is not a de Polignac number, because 316025542213013 - 212 = 316025542208917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (316025542213093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158012771106506 + 158012771106507.

It is an arithmetic number, because the mean of its divisors is an integer number (158012771106507).

Almost surely, 2316025542213013 is an apocalyptic number.

It is an amenable number.

316025542213013 is a deficient number, since it is larger than the sum of its proper divisors (1).

316025542213013 is an equidigital number, since it uses as much as digits as its factorization.

316025542213013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 316025542213013 its reverse (310312245520613), we get a palindrome (626337787733626).

The spelling of 316025542213013 in words is "three hundred sixteen trillion, twenty-five billion, five hundred forty-two million, two hundred thirteen thousand, thirteen".