Base | Representation |
---|---|
bin | 11101011100010000… |
… | …001101011001101001 |
3 | 10000121010112121122022 |
4 | 131130100031121221 |
5 | 1004220301233022 |
6 | 22304514034225 |
7 | 2166250010255 |
oct | 353420153151 |
9 | 100533477568 |
10 | 31612524137 |
11 | 1245249a307 |
12 | 6162b78975 |
13 | 2c9a4945ac |
14 | 175c67d265 |
15 | c5049dc42 |
hex | 75c40d669 |
31612524137 has 2 divisors, whose sum is σ = 31612524138. Its totient is φ = 31612524136.
The previous prime is 31612524103. The next prime is 31612524169. The reversal of 31612524137 is 73142521613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29819763856 + 1792760281 = 172684^2 + 42341^2 .
It is a cyclic number.
It is not a de Polignac number, because 31612524137 - 210 = 31612523113 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 31612524097 and 31612524106.
It is not a weakly prime, because it can be changed into another prime (31612527137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15806262068 + 15806262069.
It is an arithmetic number, because the mean of its divisors is an integer number (15806262069).
Almost surely, 231612524137 is an apocalyptic number.
It is an amenable number.
31612524137 is a deficient number, since it is larger than the sum of its proper divisors (1).
31612524137 is an equidigital number, since it uses as much as digits as its factorization.
31612524137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 30240, while the sum is 35.
The spelling of 31612524137 in words is "thirty-one billion, six hundred twelve million, five hundred twenty-four thousand, one hundred thirty-seven".
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