Base | Representation |
---|---|
bin | 1001001100110101000… |
… | …11011111111101110111 |
3 | 1010012222100002212212021 |
4 | 10212122203133331313 |
5 | 20134411124003342 |
6 | 401120500534011 |
7 | 31560613230205 |
oct | 4463243377567 |
9 | 1105870085767 |
10 | 316125609847 |
11 | 112082735693 |
12 | 513259b1307 |
13 | 23a6c924298 |
14 | 1142ca50075 |
15 | 8353217567 |
hex | 499a8dff77 |
316125609847 has 2 divisors, whose sum is σ = 316125609848. Its totient is φ = 316125609846.
The previous prime is 316125609841. The next prime is 316125609851. The reversal of 316125609847 is 748906521613.
It is a strong prime.
It is an emirp because it is prime and its reverse (748906521613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 316125609847 - 219 = 316125085559 is a prime.
It is a super-2 number, since 2×3161256098472 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 316125609794 and 316125609803.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (316125609841) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158062804923 + 158062804924.
It is an arithmetic number, because the mean of its divisors is an integer number (158062804924).
It is a 1-persistent number, because it is pandigital, but 2⋅316125609847 = 632251219694 is not.
Almost surely, 2316125609847 is an apocalyptic number.
316125609847 is a deficient number, since it is larger than the sum of its proper divisors (1).
316125609847 is an equidigital number, since it uses as much as digits as its factorization.
316125609847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 52.
The spelling of 316125609847 in words is "three hundred sixteen billion, one hundred twenty-five million, six hundred nine thousand, eight hundred forty-seven".
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