Base | Representation |
---|---|
bin | 101110000000001101000… |
… | …100111000011010100001 |
3 | 102012012220111111021002221 |
4 | 232000031010320122201 |
5 | 403243333210011223 |
6 | 10420142130311041 |
7 | 444253224540013 |
oct | 56001504703241 |
9 | 12165814437087 |
10 | 3161315313313 |
11 | 1009785096233 |
12 | 430826128481 |
13 | 19c159436911 |
14 | ad0193961b3 |
15 | 573768e8b5d |
hex | 2e00d1386a1 |
3161315313313 has 2 divisors, whose sum is σ = 3161315313314. Its totient is φ = 3161315313312.
The previous prime is 3161315313283. The next prime is 3161315313337. The reversal of 3161315313313 is 3133135131613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1619019573649 + 1542295739664 = 1272407^2 + 1241892^2 .
It is an emirp because it is prime and its reverse (3133135131613) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3161315313313 - 217 = 3161315182241 is a prime.
It is not a weakly prime, because it can be changed into another prime (3161315313613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1580657656656 + 1580657656657.
It is an arithmetic number, because the mean of its divisors is an integer number (1580657656657).
Almost surely, 23161315313313 is an apocalyptic number.
It is an amenable number.
3161315313313 is a deficient number, since it is larger than the sum of its proper divisors (1).
3161315313313 is an equidigital number, since it uses as much as digits as its factorization.
3161315313313 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21870, while the sum is 34.
The spelling of 3161315313313 in words is "three trillion, one hundred sixty-one billion, three hundred fifteen million, three hundred thirteen thousand, three hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •