Base | Representation |
---|---|
bin | 1001001100110110001… |
… | …01101001011101111101 |
3 | 1010012222221221200102221 |
4 | 10212123011221131331 |
5 | 20134420421433121 |
6 | 401121420445341 |
7 | 31561052302612 |
oct | 4463305513575 |
9 | 1105887850387 |
10 | 316134561661 |
11 | 11208779a286 |
12 | 513289a9851 |
13 | 23a71739a09 |
14 | 1142dd00509 |
15 | 8353dd4b41 |
hex | 499b16977d |
316134561661 has 2 divisors, whose sum is σ = 316134561662. Its totient is φ = 316134561660.
The previous prime is 316134561623. The next prime is 316134561671. The reversal of 316134561661 is 166165431613.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 315388944025 + 745617636 = 561595^2 + 27306^2 .
It is a cyclic number.
It is not a de Polignac number, because 316134561661 - 211 = 316134559613 is a prime.
It is a super-2 number, since 2×3161345616612 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (316134561671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 158067280830 + 158067280831.
It is an arithmetic number, because the mean of its divisors is an integer number (158067280831).
Almost surely, 2316134561661 is an apocalyptic number.
It is an amenable number.
316134561661 is a deficient number, since it is larger than the sum of its proper divisors (1).
316134561661 is an equidigital number, since it uses as much as digits as its factorization.
316134561661 is an evil number, because the sum of its binary digits is even.
The product of its digits is 233280, while the sum is 43.
The spelling of 316134561661 in words is "three hundred sixteen billion, one hundred thirty-four million, five hundred sixty-one thousand, six hundred sixty-one".
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