3162340255141 has 2 divisors, whose sum is σ = 3162340255142. Its totient is φ = 3162340255140.

The previous prime is 3162340255111. The next prime is 3162340255159. The reversal of 3162340255141 is 1415520432613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2169419681025 + 992920574116 = 1472895^2 + 996454^2 .

It is a cyclic number.

It is not a de Polignac number, because 3162340255141 - 2⁷ = 3162340255013 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3162340255141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3162340255111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1581170127570 + 1581170127571.

It is an arithmetic number, because the mean of its divisors is an integer number (1581170127571).

Almost surely, 2^{3162340255141} is an apocalyptic number.

It is an amenable number.

3162340255141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3162340255141 is an equidigital number, since it uses as much as digits as its factorization.

3162340255141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 3162340255141 its reverse (1415520432613), we get a palindrome (4577860687754).

The spelling of 3162340255141 in words is "three trillion, one hundred sixty-two billion, three hundred forty million, two hundred fifty-five thousand, one hundred forty-one".