Base | Representation |
---|---|
bin | 100011111101000001100111… |
… | …0111101101000000110100101 |
3 | 1112110202020211101120021220202 |
4 | 1013322003032331220012211 |
5 | 312422422013033404423 |
6 | 3040335250450440245 |
7 | 123420226211206133 |
oct | 10772031675500645 |
9 | 1473666741507822 |
10 | 316250504200613 |
11 | 918490a3a95564 |
12 | 2b577571b93085 |
13 | 107603aa275068 |
14 | 581486b0d2753 |
15 | 268660494b728 |
hex | 11fa0cef681a5 |
316250504200613 has 4 divisors (see below), whose sum is σ = 316250566847520. Its totient is φ = 316250441553708.
The previous prime is 316250504200573. The next prime is 316250504200621. The reversal of 316250504200613 is 316002405052613.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 316250504200613 - 224 = 316250487423397 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (316250504209613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23016995 + ... + 34092272.
It is an arithmetic number, because the mean of its divisors is an integer number (79062641711880).
Almost surely, 2316250504200613 is an apocalyptic number.
It is an amenable number.
316250504200613 is a deficient number, since it is larger than the sum of its proper divisors (62646907).
316250504200613 is an equidigital number, since it uses as much as digits as its factorization.
316250504200613 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62646906.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 316250504200613 in words is "three hundred sixteen trillion, two hundred fifty billion, five hundred four million, two hundred thousand, six hundred thirteen".
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