Base | Representation |
---|---|
bin | 100011111101000010110110… |
… | …0000100100111010101111111 |
3 | 1112110202111122002101120221222 |
4 | 1013322011230010213111333 |
5 | 312422442412323233143 |
6 | 3040340404210143555 |
7 | 123420351425462054 |
oct | 10772055404472577 |
9 | 1473674562346858 |
10 | 316253140055423 |
11 | 9184a22694a26a |
12 | 2b577b88881bbb |
13 | 1076070a38cb6c |
14 | 5814a3b1c902b |
15 | 268670b060768 |
hex | 11fa16c12757f |
316253140055423 has 4 divisors (see below), whose sum is σ = 316253176441608. Its totient is φ = 316253103669240.
The previous prime is 316253140055393. The next prime is 316253140055429. The reversal of 316253140055423 is 324550041352613.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 316253140055423 - 212 = 316253140051327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (316253140055429) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3338528 + ... + 25370298.
It is an arithmetic number, because the mean of its divisors is an integer number (79063294110402).
Almost surely, 2316253140055423 is an apocalyptic number.
316253140055423 is a deficient number, since it is larger than the sum of its proper divisors (36386185).
316253140055423 is a wasteful number, since it uses less digits than its factorization.
316253140055423 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36386184.
The product of its (nonzero) digits is 1296000, while the sum is 44.
The spelling of 316253140055423 in words is "three hundred sixteen trillion, two hundred fifty-three billion, one hundred forty million, fifty-five thousand, four hundred twenty-three".
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