Search a number
-
+
31628552149 is a prime number
BaseRepresentation
bin11101011101001101…
…010110011111010101
310000122020200220221101
4131131031112133111
51004233402132044
622310245350101
72166533154205
oct353515263725
9100566626841
1031628552149
11124605473a7
126168408331
132ca08b6b1c
141760852405
15c51ab7cd4
hex75d3567d5

31628552149 has 2 divisors, whose sum is σ = 31628552150. Its totient is φ = 31628552148.

The previous prime is 31628552117. The next prime is 31628552159. The reversal of 31628552149 is 94125582613.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19147640625 + 12480911524 = 138375^2 + 111718^2 .

It is an emirp because it is prime and its reverse (94125582613) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 31628552149 - 25 = 31628552117 is a prime.

It is a super-2 number, since 2×316285521492 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 31628552099 and 31628552108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (31628552159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15814276074 + 15814276075.

It is an arithmetic number, because the mean of its divisors is an integer number (15814276075).

Almost surely, 231628552149 is an apocalyptic number.

It is an amenable number.

31628552149 is a deficient number, since it is larger than the sum of its proper divisors (1).

31628552149 is an equidigital number, since it uses as much as digits as its factorization.

31628552149 is an evil number, because the sum of its binary digits is even.

The product of its digits is 518400, while the sum is 46.

The spelling of 31628552149 in words is "thirty-one billion, six hundred twenty-eight million, five hundred fifty-two thousand, one hundred forty-nine".