Base | Representation |
---|---|
bin | 100011111101110000011110… |
… | …1100100100011001010010011 |
3 | 1112111002212121011101012120222 |
4 | 1013323200331210203022103 |
5 | 312431044120400124210 |
6 | 3040453413114023255 |
7 | 123430421155502261 |
oct | 10773407544431223 |
9 | 1474085534335528 |
10 | 316351144145555 |
11 | 91887848681782 |
12 | 2b592b7a117b2b |
13 | 10769a28527b3c |
14 | 5819697137431 |
15 | 2689044e44655 |
hex | 11fb83d923293 |
316351144145555 has 8 divisors (see below), whose sum is σ = 385844674171344. Its totient is φ = 248932047852000.
The previous prime is 316351144145551. The next prime is 316351144145567. The reversal of 316351144145555 is 555541441153613.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 316351144145555 - 22 = 316351144145551 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 316351144145497 and 316351144145506.
It is not an unprimeable number, because it can be changed into a prime (316351144145551) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 518608432721 + ... + 518608433330.
It is an arithmetic number, because the mean of its divisors is an integer number (48230584271418).
Almost surely, 2316351144145555 is an apocalyptic number.
316351144145555 is a deficient number, since it is larger than the sum of its proper divisors (69493530025789).
316351144145555 is a wasteful number, since it uses less digits than its factorization.
316351144145555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1037216866117.
The product of its digits is 10800000, while the sum is 53.
The spelling of 316351144145555 in words is "three hundred sixteen trillion, three hundred fifty-one billion, one hundred forty-four million, one hundred forty-five thousand, five hundred fifty-five".
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